Step 1: Calculate the molecular mass of \( \text{Na}_2\text{SO}_4 \)
The molecular mass of a compound is the sum of the atomic masses of its elements.
- Atomic mass of sodium (Na) = 23 g/mol,
- Atomic mass of sulfur (S) = 32 g/mol,
- Atomic mass of oxygen (O) = 16 g/mol.
Step 2: Add the atomic masses
The molecular formula of sodium sulfate is \( \text{Na}_2\text{SO}_4 \),
which contains: - 2 sodium atoms, - 1 sulfur atom, - 4 oxygen atoms.
Thus, the molecular mass is: \[ \text{Molecular mass of Na}_2\text{SO}_4 = 2 \times 23 + 1 \times 32 + 4 \times 16 \] \[ = 46 + 32 + 64 = 142 \, \text{g/mol} \]
Answer:
Therefore, the molecular mass of \( \text{Na}_2\text{SO}_4 \) is \( 142 \, \text{g/mol} \). So, the correct answer is option (1).
Correct statements for an element with atomic number 9 are
A. There can be 5 electrons for which $ m_s = +\frac{1}{2} $ and 4 electrons for which $ m_s = -\frac{1}{2} $
B. There is only one electron in $ p_z $ orbital.
C. The last electron goes to orbital with $ n = 2 $ and $ l = 1 $.
D. The sum of angular nodes of all the atomic orbitals is 1.
Choose the correct answer from the options given below:
The energy of an electron in first Bohr orbit of H-atom is $-13.6$ eV. The magnitude of energy value of electron in the first excited state of Be$^{3+}$ is _____ eV (nearest integer value)