Question:

What is the molar specific heat at constant volume $ C_V $ of a diatomic gas molecule if one additional vibrational degree of freedom is considered?

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Each vibrational mode contributes 2 degrees of freedom: one kinetic and one potential.
  • \( \frac{5}{2} R \)
  • \( \frac{6}{2} R \)
  • \( \frac{7}{2} R \)
  • \( \frac{9}{2} R \)
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The Correct Option is C

Solution and Explanation

For a diatomic gas without vibrational modes, the degrees of freedom (D.O.F) = 5. With one vibrational mode added (which contributes 2 degrees of freedom), total D.O.F becomes 7. According to the equipartition theorem: \[ U = \frac{7}{2} RT \] So, \[ C_V = \left( \frac{dU}{dT} \right) = \frac{7}{2} R \]
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