Question:

If $ L = 40\,\text{mH} $, $ C = 100\,\mu\text{F} $, what is the angular frequency $ \omega $ at resonance?

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At resonance, the inductive and capacitive reactances are equal, and \( \omega = \frac{1}{\sqrt{LC}} \) gives the key frequency of the circuit.
  • 400
  • 100
  • 500
  • 250
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The Correct Option is C

Solution and Explanation

Resonant angular frequency is given by: \[ \omega = \frac{1}{\sqrt{LC}} = \frac{1}{\sqrt{40 \times 10^{-3} \times 100 \times 10^{-6}}} = \frac{1}{2 \times 10^{-3}} = 500 \, \text{rad/s} \]
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