\(\text{Given:}\) \[ \mu = 0.4, \quad r_1 = 160 \, \text{mm}, \quad r_2 = 190 \, \text{mm}, \quad F = 2500 \, \text{N}, \quad N = 3600 \, \text{rev/min} \] The maximum power transmitted by the clutch is given by: \[ P = \frac{2 \pi N F (r_2 - r_1) \mu}{60} \] Substituting the values: \[ P = \frac{2 \pi \times 3600 \times 2500 \times (0.19 - 0.16) \times 0.4}{60} \] \[ P = 139 \, \text{kW} \]