To determine the limiting reagent, we compare the mole ratios of the reactants to the coefficients in the balanced equation.
The balanced equation is:
\[
2H_2 + O_2 \rightarrow 2H_2O
\]
From the equation, 2 moles of \( H_2 \) react with 1 mole of \( O_2 \).
- Given 3 moles of \( H_2 \), we need \( \frac{3}{2} = 1.5 \) moles of \( O_2 \) to completely react with it.
- Since 2 moles of \( O_2 \) are available, we have excess \( O_2 \), and \( H_2 \) is the limiting reagent.
Thus, \( H_2 \) is the limiting reagent.