What is the intermediate product obtained in the preparation of phenol from aniline?
Benzene
Correct Answer: Option 2 - Benzene diazonium chloride
The preparation of phenol from aniline involves a two-step chemical process, and the key intermediate formed during this reaction is benzene diazonium chloride.
Step 1: Diazotization of Aniline
• In the first step, aniline (C6H5NH2) is reacted with nitrous acid (HNO2) in the presence of hydrochloric acid (HCl) at low temperatures (0–5°C).
• Nitrous acid is usually generated in situ by reacting sodium nitrite (NaNO2) with dilute HCl.
The reaction is:
C6H5NH2 + HNO2 + HCl → C6H5N2Cl + 2H2O
• The compound formed here is benzene diazonium chloride, which is a stable intermediate only at low temperatures.
Step 2: Hydrolysis to form Phenol
• In the second step, this intermediate benzene diazonium chloride is heated with water (hydrolysis), often in the presence of dilute acids.
• This decomposes the diazonium salt and releases nitrogen gas (N2), forming phenol (C6H5OH) as the final product.
The reaction is:
C6H5N2Cl + H2O → C6H5OH + N2 + HCl
Conclusion:
The intermediate product formed during the conversion of aniline to phenol is benzene diazonium chloride. This compound plays a critical role in many substitution reactions in aromatic chemistry and is an essential intermediate in organic synthesis.
The order of acidity of the following compounds is:
(i) o-Nitrophenol
(ii) Phenol
(iii) o-Cresol
(iv) Ethanol
Given below are two statements:
Statement I: Dimethyl ether is completely soluble in water. However, diethyl ether is soluble in water to a very small extent.
Statement II: Sodium metal can be used to dry diethyl ether and not ethyl alcohol.
In the light of the given statements, choose the correct answer from the options given below: