What is the hybridization of the central atom in \(NH_3\)?
What is the hybridization of the central atom in \(NH_3\)?
Show Hint
- sp
- sp^2
- sp^3
sp^3d
The Correct Option is C
Solution and Explanation
In \(NH_3\), the central atom is nitrogen. Nitrogen has 5 valence electrons and forms 3 single bonds with hydrogen atoms, leaving 1 lone pair. The steric number (number of bonded atoms + lone pairs) is: \[ 3 \, (\text{bonds}) + 1 \, (\text{lone pair}) = 4 \] A steric number of 4 corresponds to \(sp^3\) hybridization. Thus, the hybridization of nitrogen in \(NH_3\) is: \(\text{sp}^3\)
Top Questions on Hybridization
- At 0 K, the molecule CO exists in two alternate arrangements (CO and OC) in the solid crystal. The value of the entropy is (where thermodynamic probability \( W = k^N \)):
- CUET (PG) - 2025
- Chemistry
- Hybridization
- For 3 mol of an ideal gas \(\left[ C_{p,m} = \frac{5}{2}R \right]\), being heated from 300 K to 600 K, the change in entropy at constant pressure is
- CUET (PG) - 2025
- Chemistry
- Hybridization
Given below are two statements:
Statement (II): Structure III is most stable, as the orbitals having the lone pairs are axial, where the $ \ell p - \beta p $ repulsion is minimum. In light of the above statements, choose the most appropriate answer from the options given below:- JEE Main - 2025
- Chemistry
- Hybridization
- Explain \( [Co(NH_3)_6]^{3+} \) is an inner orbital complex whereas \( [Ni(NH_3)_6]^{2+} \) is an outer orbital complex. [At. No. Co = 27, Ni = 28]
- CBSE CLASS XII - 2025
- Chemistry
- Hybridization
Consider the following statements:
Statement-I: The products formed when diborane burns in air are \({B}_2{O}_3\), \({H}_2\), and \({O}_2\).
Statement-II: Hybridization of boron atom in orthoboric acid is \(sp^2\). The correct answer is:- AP EAPCET - 2025
- Chemistry
- Hybridization
Questions Asked in AP EAPCET exam
- The domain and range of a real valued function \( f(x) = \cos (x-3) \) are respectively.
- AP EAPCET - 2025
- Functions
- If the line $$ 4x - 3y + 7 = 0 $$ touches the circle $$ x^2 + y^2 - 6x + 4y - 12 = 0 $$ at $ (\alpha, \beta) $, then find $ \alpha + 2\beta $.
- The number of ways of selecting 3 numbers that are in Arithmetic Progression (A.P.) from the set \(\{1, 2, 3, \ldots, 100\}\) is:
- AP EAPCET - 2025
- Arithmetic Progressions
- The numerically greatest term in the expansion of $ (x + 3y)^{13} $, when $ x = \frac{1}{2},\ y = \frac{1}{3} $, is
- AP EAPCET - 2025
- Binomial theorem
- The general solution of the differential equation \(\frac{dy}{dx} + xy = 4x - 2y + 8\) is
- AP EAPCET - 2025
- Differential Equations