Step 1: Convert the decimal number to binary.
The decimal number 265 can be converted to binary as follows: \[ 265 \div 2 = 132 \, \text{remainder} \, 1 \\ 132 \div 2 = 66 \, \text{remainder} \, 0 \\ 66 \div 2 = 33 \, \text{remainder} \, 0 \\ 33 \div 2 = 16 \, \text{remainder} \, 1 \\ 16 \div 2 = 8 \, \text{remainder} \, 0 \\ 8 \div 2 = 4 \, \text{remainder} \, 0 \\ 4 \div 2 = 2 \, \text{remainder} \, 0 \\ 2 \div 2 = 1 \, \text{remainder} \, 0 \\ 1 \div 2 = 0 \, \text{remainder} \, 1 \] Thus, the binary representation of 265 is \( 100001001_2 \).
Step 2: Convert the binary number to hexadecimal.
Group the binary digits into sets of four starting from the right: \[ 1000 \, 0100 \, 1 \Rightarrow 0001 \, 0001 \, 0001 \] So, the hexadecimal representation is \( 0x109 \).
Step 3: Conclusion.
Thus, the correct hexadecimal representation of the decimal number 265 is \( 0x109 \), and the correct answer is (d).
Given an unsigned 32-bit integer \( x \), which of the following C/C++ expressions correctly toggles its bits starting from position \( p \) (with the least significant bit at position 0)?
Assume: \( x \) is the input integer; \( p \) is the starting position of the bit range (0-based, LSB at position 0); \( m \) is the number of bits to toggle; and no overflow or invalid input conditions occur. Which of the following correctly toggles \( m \) bits starting from position \( p \)?
A remote island has a unique social structure. Individuals are either "Truth-tellers" (who always speak the truth) or "Tricksters" (who always lie). You encounter three inhabitants: X, Y, and Z.
X says: "Y is a Trickster"
Y says: "Exactly one of us is a Truth-teller."
What can you definitively conclude about Z?
Consider the following statements followed by two conclusions.
Statements: 1. Some men are great. 2. Some men are wise.
Conclusions: 1. Men are either great or wise. 2. Some men are neither great nor wise. Choose the correct option: