The frequency of the rotor current (\(f_r\)) in an induction motor is given by the formula:
\[
f_r = s \times f_s
\]
Where:
- \(f_s\) is the supply frequency (50Hz),
- \(s\) is the slip.
Given that the slip is 2%, or \(s = 0.02\), the rotor frequency is:
\[
f_r = 0.02 \times 50 = 1 \, \text{Hz}
\]
Thus, the frequency of the rotor current is 1Hz, which corresponds to option (4).