What is the equivalent resistance between the points A and B of the network?
To solve for the equivalent resistance between points A and B, we first simplify the given resistances using series and parallel combinations.
Start by analyzing the network step by step: 1. Combine the resistances that are in series. 2. Combine the resistances that are in parallel. Once simplified, the equivalent resistance turns out to be 8 \( \Omega \).
Final Answer: 8 \( \Omega \).
An inductor and a resistor are connected in series to an AC source of voltage \( 144\sin(100\pi t + \frac{\pi}{2}) \) volts. If the current in the circuit is \( 6\sin(100\pi t + \frac{\pi}{2}) \) amperes, then the resistance of the resistor is: