To determine the acidity order, we need to consider the effects of the hydroxyl groups on the acidity of the benzoic acid.
Step 1: Draw the Structures
Let's draw the structures of the three compounds:
Step 2: Factors Affecting Acidity
Several factors influence the acidity of organic acids:
Step 3: Acidity Analysis of the Given Compounds
The hydroxyl group in the para position has a weaker effect on acidity because it is farther from the carboxyl group. The -OH group exhibits both +R (resonance) and -I (inductive) effects. Usually, the +R effects counteract each other, and the -I effect slightly decreases the acidity of the compound relative to benzoic acid.
The hydroxyl group in the ortho position has a stronger effect than in the para position. The ortho effect and intramolecular hydrogen bonding influence acidity. Salicylic acid benefits from intramolecular hydrogen bonding which stabilises the conjugate base, increasing its acidity.
The presence of two hydroxyl groups in the ortho positions further increases the acidity. The effect of one hydroxyl group in ortho is stabilising the conjugate base through hydrogen bonding. With two OH groups, more hydrogen bonding is possible, stabilising the anion more than in salicylic acid.
Step 4: Putting It All Together
Based on the analysis, we can conclude the following acidity order:
2, 6-dihydroxybenzoic acid > salicylic acid > 4- hydroxybenzoic acid
Conclusion
The correct order of acidity is: 2, 6-dihydroxybenzoic acid > salicylic acid > 4- hydroxybenzoic acid.
List-I | List-II | ||
(A) | 1 mol of H2O to O2 | (I) | 3F |
(B) | 1 mol of MnO-4 to Mn2+ | (II) | 2F |
(C) | 1.5 mol of Ca from molten CaCl2 | (III) | 1F |
(D) | 1 mol of FeO to Fe2O3 | (IV) | 5F |
Identify the products C, D, and F formed in the following sets of reactions.
Which one of the following is the correct order of reagents to be used to convert [A] to [X]?
A beam of light of wavelength \(\lambda\) falls on a metal having work function \(\phi\) placed in a magnetic field \(B\). The most energetic electrons, perpendicular to the field, are bent in circular arcs of radius \(R\). If the experiment is performed for different values of \(\lambda\), then the \(B^2 \, \text{vs} \, \frac{1}{\lambda}\) graph will look like (keeping all other quantities constant).