Step 1: Understanding bond order.
Bond order can be determined using molecular orbital theory. For the B\(_2\) molecule, the molecular orbitals are filled as follows:
- The bonding electrons in \(\sigma_{2s}\) and \(\sigma^*_{2s}\) cancel out, leaving a bond order of 0.
Step 2: Conclusion.
The bond order of B\(_2\) is 0, meaning there is no bond between the two boron atoms.