What is molarity of pure water?
Density of water = 1 g/cm3 and its molecular weight is 18. So, 1000 cm3 of water will weigh 1000 g of water.
Now, we know that molarity \(=\frac{\text { Mass of water }}{\text { Molecular weight }}\) \(=\frac{1000}{18}\) \(=55.56 \,M\)
\(Molarity = \frac{\text { Mass of water }}{\text { Molecular weight }}\)
\(Molarity = \frac{1000}{18}\)
\(Molarity = 55.56 M\)
Hence, the molarity of water is 55.56 M.
A substance 'X' (1.5 g) dissolved in 150 g of a solvent 'Y' (molar mass = 300 g mol$^{-1}$) led to an elevation of the boiling point by 0.5 K. The relative lowering in the vapour pressure of the solvent 'Y' is $____________ \(\times 10^{-2}\). (nearest integer)
[Given : $K_{b}$ of the solvent = 5.0 K kg mol$^{-1}$]
Assume the solution to be dilute and no association or dissociation of X takes place in solution.
A solution is a homogeneous mixture of two or more components in which the particle size is smaller than 1 nm.
For example, salt and sugar is a good illustration of a solution. A solution can be categorized into several components.
The solutions can be classified into three types:
On the basis of the amount of solute dissolved in a solvent, solutions are divided into the following types: