Correct Answer: Feminist historiography is a branch of history that studies the past from the perspective of women.
Step 1: Understanding Feminist Historiography
Feminist historiography studies history through the lens of women’s experiences and contributions. It challenges traditional history that often ignored women, highlighting their roles, struggles, and achievements throughout time.
Step 2: Role of Women in History
It examines women’s participation in various fields like politics, culture, and economics. Feminist historians explore how women contributed to social progress and how gender relations evolved through history.
Step 3: Criticizing Traditional Historiography
Traditional history often prioritized male perspectives. Feminist historiography critiques this imbalance and brings attention to women’s significant yet overlooked impact on historical events and cultural development.
Step 4: Key Themes
Feminist historians study gender inequality, women’s rights movements, labor, suffrage, and representation. They aim to rewrite history in a more inclusive way that represents all genders fairly.
\[ \text{Feminist historiography examines history from women’s perspectives, challenging traditional male-centered narratives.} \]
Complete the following concept map :
Complete the following activity to prove that the sum of squares of diagonals of a rhombus is equal to the sum of the squares of the sides.
Given: PQRS is a rhombus. Diagonals PR and SQ intersect each other at point T.
To prove: PS\(^2\) + SR\(^2\) + QR\(^2\) + PQ\(^2\) = PR\(^2\) + QS\(^2\)
Activity: Diagonals of a rhombus bisect each other.
In \(\triangle\)PQS, PT is the median and in \(\triangle\)QRS, RT is the median.
\(\therefore\) by Apollonius theorem,
\[\begin{aligned} PQ^2 + PS^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(I)} \\ QR^2 + SR^2 &= \boxed{\phantom{X}} + 2QT^2 \quad \dots \text{(II)} \\ \text{Adding (I) and (II),} \quad PQ^2 + PS^2 + QR^2 + SR^2 &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \\ &= 2(PT^2 + \boxed{\phantom{X}}) + 4QT^2 \quad (\text{RT = PT}) \\ &= 4PT^2 + 4QT^2 \\ &= (\boxed{\phantom{X}})^2 + (2QT)^2 \\ \therefore \quad PQ^2 + PS^2 + QR^2 + SR^2 &= PR^2 + \boxed{\phantom{X}} \\ \end{aligned}\]