What is change in internal energy if a system gains xJ of heat and yJ work is done on it?
The change in internal energy (ΔU) of a system can be determined using the first law of thermodynamics, which states that the change in internal energy is equal to the heat (Q) added to the system minus the work (W) done by the system:
ΔU = Q - W
In this case, the system gains xJ of heat (Q = xJ), and yJ of work is done on it (W = yJ).
Substituting these values into the equation, we have:
ΔU = xJ - yJ
Simplifying further, we get:
ΔU = (x - y)J
Therefore, the correct option is (A) x - y.
Three conductors of same length having thermal conductivity \(k_1\), \(k_2\), and \(k_3\) are connected as shown in figure. Area of cross sections of 1st and 2nd conductor are same and for 3rd conductor it is double of the 1st conductor. The temperatures are given in the figure. In steady state condition, the value of θ is ________ °C. (Given: \(k_1\) = 60 Js⁻¹m⁻¹K⁻¹,\(k_2\) = 120 Js⁻¹m⁻¹K⁻¹, \(k_3\) = 135 Js⁻¹m⁻¹K⁻¹)