What happens when
(i)n-butyl chloride is treated with alcoholic KOH
(ii)bromobenzene is treated with Mg in the presence of dry ether
(iii)chlorobenzene is subjected to hydrolysis
(iv) ethyl chloride is treated with aqueous KOH
(v)methyl bromide is treated with sodium in the presence of dry ether
(vi)methyl chloride is treated with KCN?
(i)When n−butyl chloride is treated with alcoholic KOH, the formation of but−l−ene takes place. This reaction is a dehydrohalogenation reaction.
(ii)When n−butyl chloride is treated with alcoholic KOH, the formation of but−l−ene takes place. This reaction is a dehydrohalogenation reaction.
(iii)Chlorobenzene does not undergo hydrolysis under normal conditions. However,it undergoes hydrolysis when heated in an aqueous sodium hydroxide solution at a temperature of 623 K and a pressure of 300 atm to form phenol.
(iv)When ethyl chloride is treated with aqueous KOH, it undergoes hydrolysis to form ethanol.
(v)When ethyl chloride is treated with aqueous KOH, it undergoes hydrolysis to form ethanol.
(vi)When methyl chloride is treated with KCN, it undergoes a substitution reaction to give methyl cyanide.
A compound (A) with molecular formula $C_4H_9I$ which is a primary alkyl halide, reacts with alcoholic KOH to give compound (B). Compound (B) reacts with HI to give (C) which is an isomer of (A). When (A) reacts with Na metal in the presence of dry ether, it gives a compound (D), C8H18, which is different from the compound formed when n-butyl iodide reacts with sodium. Write the structures of A, (B), (C) and (D) when (A) reacts with alcoholic KOH.