Question:

What happens when D-Glucose is treated with hydroxylamine?

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Reaction with hydroxylamine confirms the presence of an aldehyde or ketone group in a molecule.
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Solution and Explanation

Step 1: D-Glucose contains an aldehyde group (–CHO) at its terminal carbon.
Step 2: Hydroxylamine (\( NH_2OH \)) reacts with aldehydes to form oximes.
Step 3: Therefore, when D-Glucose is treated with hydroxylamine, it forms a glucose oxime: \[ \text{Glucose (–CHO)} + NH_2OH \longrightarrow \text{Glucose oxime (–CH=NOH)} \]
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