Step 1: D-Glucose contains an aldehyde group (–CHO) at its terminal carbon. Step 2: Hydroxylamine (\( NH_2OH \)) reacts with aldehydes to form oximes. Step 3: Therefore, when D-Glucose is treated with hydroxylamine, it forms a glucose oxime: \[ \text{Glucose (–CHO)} + NH_2OH \longrightarrow \text{Glucose oxime (–CH=NOH)} \]