Question:

What back emf is induced in a coil of self-inductance 0.008 H when the current in the coil is changing at the rate of 110 A/s?

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The induced back emf in a coil is proportional to the rate of change of current and the self-inductance of the coil.
Updated On: Mar 25, 2025
  • 0.88V
  • 0.78V
  • 0.98V
  • None
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The Correct Option is A

Solution and Explanation

The induced emf \( \mathcal{E} \) is given by: \[ \mathcal{E} = L \frac{dI}{dt} \] Where:
- \( L = 0.008 \, \text{H} \),
- \( \frac{dI}{dt} = 110 \, \text{A/s} \). Substituting the values: \[ \mathcal{E} = 0.008 \times 110 = 0.88 \, \text{V} \]
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