Question

What are Y and Z respectively in the following reaction sequence? \begin{center} \includegraphics[]{155.png} \end{center}

• A. \includegraphics[]{155a.png}
• B. \includegraphics[]{155b.png}
• C. \includegraphics[]{155c.png}
• D. \includegraphics[]{155d.png}

Hint:

In electrophilic substitution, chlorine directs the incoming nitro group to the para-position due to its electron-withdrawing inductive effect.

Answer 1

The Correct Option is B

Step 1: Nitration of Chlorobenzene
- Reaction: Chlorobenzene undergoes nitration with HNO\(_3\)/H\(_2\)SO\(_4\).
- The major product is p-nitrochlorobenzene due to the electron-withdrawing effect of chlorine. Step 2: Conversion to Phenol
- Reaction: The chlorine in p-nitrochlorobenzene is replaced by OH under fused NaOH at high temperature (443K).
- The resulting compound is p-nitrophenol. Step 3: Confirming the Correct Option
- The correct Y is p-nitrochlorobenzene.
- The correct Z is p-nitrophenol.
Thus, the correct answer is the option with p-nitrophenol.