To balance the redox reaction, we apply ion-electron method in acidic medium:
\[
6 \text{Fe}^{2+} + 14 \text{H}^{+} + \text{Cr}_2\text{O}_7^{2-} \rightarrow 6 \text{Fe}^{3+} + 2 \text{Cr}^{3+} + 7 \text{H}_2\text{O}
\]
Comparing coefficients, we get \( x = 6, y = 14, z = 1 \).