Question:
What are X and Y respectively in the following reactions?
\( \text{X} + \text{D}_2\text{O} \rightarrow \text{CD}_2 + \text{P} \)
\( \text{Y} + \text{D}_2\text{O} \rightarrow \text{CD}_4 + \text{Q} \)
What are X and Y respectively in the following reactions?
\( \text{X} + \text{D}_2\text{O} \rightarrow \text{CD}_2 + \text{P} \)
\( \text{Y} + \text{D}_2\text{O} \rightarrow \text{CD}_4 + \text{Q} \)
\( \text{X} + \text{D}_2\text{O} \rightarrow \text{CD}_2 + \text{P} \)
\( \text{Y} + \text{D}_2\text{O} \rightarrow \text{CD}_4 + \text{Q} \)
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Metal carbides form hydrocarbons on hydrolysis. Use deuterium analogs here.
Updated On: May 18, 2025
- AlCl\textsubscript{3}, CaCl\textsubscript{2}
- Be\textsubscript{2}C, Al\textsubscript{4}C\textsubscript{3}
- Al\textsubscript{4}C\textsubscript{3}, CaC\textsubscript{2}
- CaC\textsubscript{2}, Al\textsubscript{4}C\textsubscript{3}
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The Correct Option is D
Solution and Explanation
CaC\textsubscript{2} reacts with D\textsubscript{2}O to form CD\textsubscript{2}, and Al\textsubscript{4}C\textsubscript{3} reacts to form CD\textsubscript{4}, just like the corresponding hydrocarbon analogues:
CaC\textsubscript{2} + 2D\textsubscript{2}O → C\textsubscript{2}D\textsubscript{2}, and Al\textsubscript{4}C\textsubscript{3} + 12D\textsubscript{2}O → 4Al(OD)\textsubscript{3} + 3CD\textsubscript{4}.
CaC\textsubscript{2} + 2D\textsubscript{2}O → C\textsubscript{2}D\textsubscript{2}, and Al\textsubscript{4}C\textsubscript{3} + 12D\textsubscript{2}O → 4Al(OD)\textsubscript{3} + 3CD\textsubscript{4}.
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