Question:
What are \(X\) and \(Y\) respectively in the following reaction?
What are \(X\) and \(Y\) respectively in the following reaction?
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Friedel-Crafts alkylation introduces alkyl groups to an aromatic ring, while oxidation with KMnO\(_4\) converts alkyl groups (-CH\(_3\), -CH\(_2\)R) into carboxylic acids (-COOH) when benzylic hydrogen is present.
Updated On: Mar 26, 2025
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The Correct Option is C
Solution and Explanation
The reaction involves the following steps:
1. Step 1: Friedel-Crafts Alkylation
- The benzyl halide (CH3Br) reacts with AlCl3 to form a benzyl carbocation, which undergoes an electrophilic substitution on the benzene ring.
- This results in the formation of p-chlorotoluene (X) as the major product.
2. Step 2: Oxidation with KMnO4 in Basic Medium
- The methyl group (-CH3) in p-chlorotoluene undergoes oxidation by KMnO4 to form a carboxyl (-COOH) group.
- The final product Y is p-chlorobenzoic acid.
Thus, the correct transformation follows:
This corresponds to Option (3).
1. Step 1: Friedel-Crafts Alkylation
- The benzyl halide (CH3Br) reacts with AlCl3 to form a benzyl carbocation, which undergoes an electrophilic substitution on the benzene ring.
- This results in the formation of p-chlorotoluene (X) as the major product.
2. Step 2: Oxidation with KMnO4 in Basic Medium
- The methyl group (-CH3) in p-chlorotoluene undergoes oxidation by KMnO4 to form a carboxyl (-COOH) group.
- The final product Y is p-chlorobenzoic acid.
Thus, the correct transformation follows:
X = p-chlorotoluene, Y = p-chlorobenzoic acidThis corresponds to Option (3).
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