Question:

Vibhuti bought a car worth ₹10,25,000 and made a down payment of ₹4,00,000. The balance is to be paid in 3 years by equal monthly installments at an interest rate of 12% p.a. The EMI that Vibhuti has to pay for the car is:
(Use \( (1.01)^{-36} = 0.7 \))

Updated On: Jun 2, 2025
  • ₹20,700.85
  • ₹27,058.87
  • ₹25,708.89

  • ₹20,833.33

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The Correct Option is D

Approach Solution - 1

To find the EMI (Equated Monthly Installment) Vibhuti has to pay, we can use the formula for EMI:
\[ \text{EMI} = \frac{P \times r \times (1+r)^n}{(1+r)^n-1} \]
where:
  • \( P \) = Principal loan amount
  • \( r \) = Monthly interest rate
  • \( n \) = Number of installments
Step 1: Calculate the Principal Amount
The cost of the car is ₹10,25,000 and a down payment of ₹4,00,000 is made. Thus, the principal amount to be financed is:
\( P = 10,25,000 - 4,00,000 = 6,25,000 \)
Step 2: Convert Annual Interest Rate to Monthly
The annual interest rate is 12%. Hence, the monthly interest rate is:
\( r = \frac{12}{100 \times 12} = 0.01 \)
Step 3: Determine the Number of Installments
Since the balance is to be paid over 3 years with monthly installments:
\( n = 3 \times 12 = 36 \)
Step 4: Substitute in the EMI Formula
Substitute the values into the EMI formula:
\[ \text{EMI} = \frac{6,25,000 \times 0.01 \times (1.01)^{36}}{(1.01)^{36}-1} \]
Given \( (1.01)^{-36} = 0.7 \), we find \( (1.01)^{36} \) by taking reciprocal:
\( (1.01)^{36} = \frac{1}{0.7} \approx 1.4286 \)
\[ \text{EMI} = \frac{6,25,000 \times 0.01 \times 1.4286}{1.4286-1} \]
\[ = \frac{6,25,000 \times 0.01 \times 1.4286}{0.4286} \]
\[ = \frac{8,937.5}{0.4286} \approx 20,833.33 \]
Thus, the EMI Vibhuti has to pay is ₹20,833.33.
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Approach Solution -2

The formula for EMI is:
$EMI = P \cdot \frac{r(1 + r)^n}{(1 + r)^n - 1}$,
where:
$P$: Loan amount $= 6,25,000$,
$r$: Monthly interest rate $= \frac{12}{12}\% = 1\% = 0.01$,
$n$: Loan tenure in months $= 36$.
Substituting the values:
$EMI = 6,25,000 \cdot \frac{0.01(1 + 0.01)^{36}}{(1 + 0.01)^{36} - 1}$.
Given:
$(1.01)^{-36} = 0.7 \implies (1.01)^{36} = \frac{1}{0.7} = 1.4286$.
Simplify:
$EMI = 6,25,000 \cdot \frac{0.01 \cdot 1.4286}{1.4286 - 1}$.
Numerator:
$0.01 \cdot 1.4286 = 0.014286$.
Denominator:
$1.4286 - 1 = 0.4286$.
Simplify the fraction:
$\frac{0.014286}{0.4286} \approx 0.03333$.
Thus:
$EMI = 6,25,000 \cdot 0.03333 = 20,833.33$.
Final Answer:
20,833.33

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