Question:

Valve A fills a bathtub in 10 hours and valve B fills it in 15 hours. A and B are opened together; later B is closed. The tub is filled in 8 hours in total. For how long was B open?

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In mixed-time problems, translate to rates, write a single “total work = 1” equation, and solve for the unknown time.
Updated On: Sep 2, 2025
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The Correct Option is C

Solution and Explanation


Rates: A fills \(1/10\) of the tub per hour; B fills \(1/15\) per hour.
Let B be open for \(t\) hours. A is open the whole \(8\) hours.
Work equation: \[ \underbrace{8\cdot\frac{1}{10}}_{\text{A's work}} \;+\; \underbrace{t\cdot\frac{1}{15}}_{\text{B's work}} \;=\;1. \] So \(\frac{8}{10}+\frac{t}{15}=1\). Hence \(\frac{t}{15}=1-\frac{8}{10}=\frac{1}{5}\), giving \(t=3\ \text{hours}\).
[2mm] \[ \boxed{3\ \text{hours}} \]
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