Using the table, which course has the lowest average enrollment across the three years? 
- Step 1: Calculate total for Course A. Sum: $50 + 55 + 60 = 165$. Average: $165 \div 3 = 55$.
- Step 2: Calculate total for Course B. Sum: $60 + 65 + 70 = 195$. Average: $195 \div 3 = 65$.
- Step 3: Calculate total for Course C. Sum: $40 + 45 + 50 = 135$. Average: $135 \div 3 = 45$.
- Step 4: Calculate total for Course D. Sum: $30 + 35 + 40 = 105$. Average: $105 \div 3 = 35$.
- Step 5: Compare averages. Course D: 35, Course C: 45, Course A: 55, Course B: 65. Course D has the lowest average.
- Step 6: Final conclusion. Option (4) Course D is the correct answer.

In a sequence of numbers, each term is generated by multiplying the previous term by 2 and then subtracting 1. If the first term is 3, what is the fourth term in the sequence?
A pie chart shows the distribution of students across 5 faculties in a university. If 20% are in Arts, 25% in Science, 15% in Law, 30% in Engineering, and the rest in Commerce, what is the angle (in degrees) for Commerce?
For any natural number $k$, let $a_k = 3^k$. The smallest natural number $m$ for which \[ (a_1)^1 \times (a_2)^2 \times \dots \times (a_{20})^{20} \;<\; a_{21} \times a_{22} \times \dots \times a_{20+m} \] is: