The electronic configuration of Beryllium is \(1s^2\; 2s^2\).
The molecular orbital electronic configuration for \(Be_2\) molecule can be written as:
\(\sigma^2_{1s} \sigma^{*2}_{1s} \sigma^2_{2s} \sigma^{*2}_{2s}\)
Hence, the bond order for \(Be_2\) is \(\frac{1}{2}(N_b-N_a)\)
Where,
\(N_b\) = Number of electrons in bonding orbitals
\(N_a\) = Number of electrons in anti-bonding orbitals
\(\therefore\) Bond order of \(Be_2\) =\(\frac{1}{2}(4-4)\) = \(0\)
A negative or zero bond order means that the molecule is unstable.
Hence, \(Be_2\) molecule does not exist.
The total number of molecular orbitals formed from 2s and 2p atomic orbitals of a diatomic molecule is _________.
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.