The electronic configuration of Beryllium is \(1s^2\; 2s^2\).
The molecular orbital electronic configuration for \(Be_2\) molecule can be written as:
\(\sigma^2_{1s} \sigma^{*2}_{1s} \sigma^2_{2s} \sigma^{*2}_{2s}\)
Hence, the bond order for \(Be_2\) is \(\frac{1}{2}(N_b-N_a)\)
Where,
\(N_b\) = Number of electrons in bonding orbitals
\(N_a\) = Number of electrons in anti-bonding orbitals
\(\therefore\) Bond order of \(Be_2\) =\(\frac{1}{2}(4-4)\) = \(0\)
A negative or zero bond order means that the molecule is unstable.
Hence, \(Be_2\) molecule does not exist.
Regarding the molecular orbital (MO) energy levels for homonuclear diatomic molecules, the INCORRECT statement(s) is (are):
Which of the following statement is true with respect to H\(_2\)O, NH\(_3\) and CH\(_4\)?
(A) The central atoms of all the molecules are sp\(^3\) hybridized.
(B) The H–O–H, H–N–H and H–C–H angles in the above molecules are 104.5°, 107.5° and 109.5° respectively.
(C) The increasing order of dipole moment is CH\(_4\)<NH\(_3\)<H\(_2\)O.
(D) Both H\(_2\)O and NH\(_3\) are Lewis acids and CH\(_4\) is a Lewis base.
(E) A solution of NH\(_3\) in H\(_2\)O is basic. In this solution NH\(_3\) and H\(_2\)O act as Lowry-Bronsted acid and base respectively.
Such a group of atoms is called a molecule. Obviously, there must be some force that holds these constituent atoms together in the molecules. The attractive force which holds various constituents (atoms, ions, etc.) together in different chemical species is called a chemical bond.
There are 4 types of chemical bonds which are formed by atoms or molecules to yield compounds.