Step 1: Understanding the reaction with AgNO\(_3\).
When a coordination compound reacts with AgNO\(_3\) to give a white precipitate of AgCl, it indicates the presence of free chloride ions (\(\text{Cl}^-\)) in the solution. The number of such free chloride ions depends on the charge of the coordination complex.
Step 2: Analyzing the options.
This compound has 1 free \(\text{Cl}^-\) ion in solution. However, it exhibits geometrical isomerism due to the cis/trans arrangement of the two chlorides within the coordination sphere, so it is incorrect.
This compound has 2 free \(\text{Cl}^-\) ions in solution. Since all ligands within the coordination sphere are monodentate and symmetrical, it does not exhibit geometrical isomerism, making this option correct.
This compound has 3 free \(\text{Cl}^-\) ions in solution. It has no geometrical isomers as all ligands are identical, making this option correct.
This compound does not have any free \(\text{Cl}^-\) ions in solution, as all chlorides are within the coordination sphere. Moreover, it exhibits geometrical isomerism, making this option incorrect.
Step 3: Conclusion.
The compounds \([\text{Cr}(\text{OH}_2)_5\text{Cl}]\text{Cl}_2\) and \([\text{Cr}(\text{OH}_2)_6]\text{Cl}_3\) satisfy the conditions given in the question, making options (B) and (C) correct.