Question:

Unmesh is facing Jayesh and when he hears a bell ring he turns towards Rajesh by making 90 shift. He continues to do this every time the bell rings. If the bell rang 3926 times, whom will Unmesh be facing?
sitting/standing arrangment

Updated On: Sep 3, 2025
  • Rajesh
  • Mahesh
  • Suresh
  • layesh
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The Correct Option is B

Solution and Explanation

To determine whom Unmesh will be facing after the bell rings 3926 times, we need to understand the sequence of 90-degree turns he makes. If Unmesh starts facing Jayesh and turns 90 degrees each time the bell rings, Unmesh's position after each turn will be as follows:
1. Starting facing Jayesh
2. One bell ring (90-degree turn): Faces Rajesh
3. Two bell rings (180-degree total turn): Faces Mahesh
4. Three bell rings (270-degree total turn): Faces Suresh
5. Four bell rings (360-degree full circle): Back to facing Jayesh
The pattern repeats every four rings. To find whom Unmesh faces after 3926 rings, we calculate the remainder of 3926 divided by 4, as it determines his final position in the sequence.
Calculating 3926 % 4:
3926 divided by 4 equals 981 with a remainder of 2.
Since the remainder is 2, Unmesh will be facing Mahesh after the 3926th bell ring.
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