Question

$ U $ is the $ PE $ of an oscillating particle and $ F $ is the force acting on it at a given instant. Which of the following is true ?

• A. $ \frac{U}{F} + x = 0 $
• B. $ \frac{2U}{F} + x = 0 $
• C. $ \frac{F}{U} + x = 0 $
• D. $ \frac{F}{2U} + x = 0 $

Answer 1

The Correct Option is B

The potential energy, $U=\frac{1}{2} k x^{2}$
$2 U=k x^{2}$
$2 U=-F x \,\,\,\,[\because F=-k x]$
or $\,\,\ \frac{2 U}{F} =-x $
or $ \,\,\,\frac{2 U}{F}+x =0 $