Question

Two years ago, population of a city was \(16,52,600 \)which increased by \( 10\%\) in the first year and by \(15\%\) in the second year. Find the present population of the city.

• A. 20,83,708
• B. 19,08,753
• C. 18,60,539
• D. 20,90,539

Answer 1

The Correct Option is D

To determine the present population of the city, we need to calculate the compounded increase in population over the two-year period. Start with the initial population two years ago, which is \( 16,52,600 \).

First, calculate the population after the first year with a \( 10\% \) increase:

\( \text{Population after 1 year} = 16,52,600 + (16,52,600 \times 0.10) \)

\( = 16,52,600 \times 1.10 \)

\( = 18,17,860 \)

Next, calculate the population after the second year with a \( 15\% \) increase:

\( \text{Population after 2 years} = 18,17,860 + (18,17,860 \times 0.15) \)

\( = 18,17,860 \times 1.15 \)

\( = 20,90,539 \)

Thus, the present population of the city is \( 20,90,539 \).