
We need to analyze the relationship between load, elongation, Young's modulus, length, and cross-sectional area to determine the correct statements.
Step 1: Recall the Formula for Young's Modulus
Young's modulus \(Y\) is defined as: \[Y = \frac{\text{Stress}}{\text{Strain}} = \frac{F/A}{\Delta L/L_0}\] where:
We can rearrange this formula to express the elongation \(x\) as: \[x = \frac{F L_0}{A Y}\] or, equivalently, \[F = \frac{AY}{L_0} x\]
Step 2: Analyze the Graph
The graph plots \(F\) (Load) vs. \(x\) (elongation). This represents a linear relationship, and the slope of the graph is given by: \[\text{Slope} = \frac{F}{x} = \frac{AY}{L_0}\]
From the graph, we can observe that the slope of line \(A\) is greater than the slope of line \(B\). Therefore: \[\frac{A_A Y_A}{L_A} > \frac{A_B Y_B}{L_B}\] where \(A_A\) and \(A_B\) are the cross-sectional areas of wires \(A\) and \(B\), and \(Y_A\) and \(Y_B\) are their respective Young's moduli.
Step 3: Apply Given Conditions
We are given that the wires are made of the same material, which means \(Y_A = Y_B\). We are also given that the wires have the same length, so \(L_A = L_B\). Therefore, the inequality simplifies to: \[A_A > A_B\]
Step 4: Determine the Correct Statements
Conclusion
The correct statements are:
\( x \) is a peptide which is hydrolyzed to 2 amino acids \( y \) and \( z \). \( y \) when reacted with HNO\(_2\) gives lactic acid. \( z \) when heated gives a cyclic structure as below:

A steel wire of length 2 m and Young's modulus \( 2.0 \times 10^{11} \, \text{N/m}^2 \) is stretched by a force. If Poisson's ratio and transverse strain for the wire are \( 0.2 \) and \( 10^{-3} \) respectively, then the elastic potential energy density of the wire is \( \times 10^6\), in SI units .
Two slabs with square cross section of different materials $(1,2)$ with equal sides $(l)$ and thickness $\mathrm{d}_{1}$ and $\mathrm{d}_{2}$ such that $\mathrm{d}_{2}=2 \mathrm{~d}_{1}$ and $l>\mathrm{d}_{2}$. Considering lower edges of these slabs are fixed to the floor, we apply equal shearing force on the narrow faces. The angle of deformation is $\theta_{2}=2 \theta_{1}$. If the shear moduli of material 1 is $4 \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$, then shear moduli of material 2 is $\mathrm{x} \times 10^{9} \mathrm{~N} / \mathrm{m}^{2}$, where value of x is _______ .
A quantity \( X \) is given by: \[ X = \frac{\epsilon_0 L \Delta V}{\Delta t} \] where:
- \( \epsilon_0 \) is the permittivity of free space,
- \( L \) is the length,
- \( \Delta V \) is the potential difference,
- \( \Delta t \) is the time interval.
The dimension of \( X \) is the same as that of:
