Question

Two springs with spring constants \(K_1 = 1500 \, \text{N/m}\) and \(K_2 = 3000 \, \text{N/m}\) are stretched by the same force. The ratio of potential energy stored in spring will be

• A. 4 : 1
• B. 1 : 4
• C. 1 : 2
• D. 2 : 1

Hint:

The potential energy stored in a spring is inversely proportional to its spring constant when the same force is applied.

Answer 1

The Correct Option is A

The potential energy stored in a spring is given by: \[ E = \frac{1}{2} k x^2 \] Since both springs are stretched by the same force, their elongation \(x\) will be inversely proportional to the spring constant \(k\). Thus, the potential energy ratio is \(4 : 1\).