Two spheres of masses m and M are situated in the air and the gravitational force between them is F. The space around the masses in now filled with a liquid of specific density 3. The gravitational force will now be:
3F
F
\(\frac{F}{3}\)
\(\frac{F}{9}\)
Gravitational force does not depend on the medium.
In this case time of flight of a ball ≥ 2 × 2 = 4 sec.
∴ Time of flight = 2u/g ≥4
\(\Rightarrow\) u ≥ 2g \(\Rightarrow\) u ≥ 19.6 m/s (∴g = 9.8 m/s2)
Net gravitational force at the center of a square is found to be \( F_1 \) when four particles having masses \( M, 2M, 3M \) and \( 4M \) are placed at the four corners of the square as shown in figure, and it is \( F_2 \) when the positions of \( 3M \) and \( 4M \) are interchanged. The ratio \( \dfrac{F_1}{F_2} = \dfrac{\alpha}{\sqrt{5}} \). The value of \( \alpha \) is 

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The output (Y) of the given logic implementation is similar to the output of an/a …………. gate.
Gravitational force is a central force that depends only on the position of the test mass from the source mass and always acts along the line joining the centers of the two masses.
According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,
By combining equations (1) and (2) we get,
F ∝ M1M2/r2
F = G × [M1M2]/r2 . . . . (7)
Or, f(r) = GM1M2/r2 [f(r)is a variable, Non-contact, and conservative force]