Separation of slits $d=4\, mm =4 \times 10^{-3} m$
Wavelength $\lambda=6000\, ?=6 \times 10^{-7} m$
Distance of screen $D=2\, m$
Fringe width $\beta =\frac{\lambda D}{d}$
$=\frac{6 \times 10^{-7} \times 2}{4 \times 10^{-3}}$
$=3 \times 10^{-4} m$
$=0.3\, mm$