According to the photoelectric equation:
\[
K.E_{\text{max}} = E_{\text{photon}} - \phi
\]
Given:
- Energy of each photon = \(2~\text{eV}\)
- Work function \(\phi = 3~\text{eV}\)
Even if two photons arrive simultaneously, photoelectric effect requires single photon interaction per electron. So only \(2~\text{eV}\) is available, which is less than the work function.
Hence, no photoelectrons are emitted, and:
\[
K.E_{\text{max}} = 0~\text{eV}
\]