Two particles of mass $5\,kg$ and $10\,kg$ respectively are attached to the two ends of a rigid rod of length 1m with negligible mass.
The centre of mass of the system from the $5\,kg$ particle is nearly at a distance of :
- 33 cm
- 50 cm
- 67 cm
- 80 cm
The Correct Option is C
Solution and Explanation
$x_{cm}=\frac{m_{1}x_{1}+m_{2}x_{2}}{m_{1}+m_{2}}$
$=\frac{5 \times 0+100 \times 10}{5+10}$
$=\frac{200}{2}$
$=66.66\,cm$
$x_{cm}=67\,cm$
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Concepts Used:
Center of Mass
The center of mass of a body or system of a particle is defined as a point where the whole of the mass of the body or all the masses of a set of particles appeared to be concentrated.
The formula for the Centre of Mass:
Center of Gravity
The imaginary point through which on an object or a system, the force of Gravity is acted upon is known as the Centre of Gravity of that system. Usually, it is assumed while doing mechanical problems that the gravitational field is uniform which means that the Centre of Gravity and the Centre of Mass is at the same position.