Question:

Two metals $X$ and $Y$ belong to the second group of periodic table. $X$ forms insoluble oxide but soluble sulphate. $Y$ forms a soluble oxide but insoluble sulphate. Hydroxide of metal $X$ is soluble in $NaOH$ while that of metal $Y$ is insoluble in $NaOH$. What are metals $X$ and $Y$ ?

Updated On: Jul 7, 2022
  • $X = Be$, $Y = Ba$
  • $X = Mg$, $Y=Ca$
  • $X= Ca$, $Y = Sr$
  • $X = Ba$, $Y = Mg$
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The Correct Option is A

Solution and Explanation

$BeO$ - Insoluble, $BeSO_4$ - Soluble $BaO$ - Soluble, $BaSO_4$ - Insoluble $Be(OH)_2$ - Soluble in $NaOH$ $Ba(OH)_2$ - Insoluble in $NaOH$
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Concepts Used:

Group 2 Elements

The group two or alkaline earth metals are s-block elements with two electrons in their s-orbital. They are alkaline earth metals. They are named so because of the alkaline nature of the hydroxides and oxides.

Alkaline earth metals are characterized by two s-electrons. This group of elements includes:

  • Beryllium (Be)
  • Magnesium (Mg)
  • Calcium (Ca)
  • Strontium (Sr)
  • Barium (Ba)
  • Radium (Ra)

Elements whose atoms have their s-subshell filled with their two valence electrons are called alkaline earth metals. Their general electronic configuration is [Noble gas] ns2. They occupy the second column of the periodic table and so-called as group two metals also.