Question:
Two metallic wires 'A' and 'B' are having same cross-sectional areas and same current passes through them. Find ratio of drift velocity of electrons in wire 'A' and 'B'.
[electron density of wire A = 8.0×1028m-3 and electron density of wire B = 9.0×1028m-3]
Two metallic wires 'A' and 'B' are having same cross-sectional areas and same current passes through them. Find ratio of drift velocity of electrons in wire 'A' and 'B'.
[electron density of wire A = 8.0×1028m-3 and electron density of wire B = 9.0×1028m-3]
[electron density of wire A = 8.0×1028m-3 and electron density of wire B = 9.0×1028m-3]
Updated On: Apr 29, 2024
- \(\frac 89\)
- \(\frac 98\)
- \(\frac {16}{27}\)
- \(\frac {27}{16}\)
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The Correct Option is B
Solution and Explanation
The correct option is (B): \(\frac 98\).
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