Question:

Two metallic wires 'A' and 'B' are having same cross-sectional areas and same current passes through them. Find ratio of drift velocity of electrons in wire 'A' and 'B'.
[electron density of wire A = 8.0×1028m-3 and electron density of wire B = 9.0×1028m-3]

Updated On: Apr 29, 2024
  • 89\frac 89
  • 98\frac 98
  • 1627\frac {16}{27}
  • 2716\frac {27}{16}
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The Correct Option is B

Solution and Explanation

The correct option is (B): 98\frac 98.
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