Question:
Two masses $ m_1 $ and $ m_2 $ are connected by a massless string over a fixed pulley. If $ m_1 > m_2 $ , $ m_1 $ will move downward and $ m_2 $ will move upward. What is the acceleration with which the combination o f two masses will move?
( $ g = $ acceleration due to gravity)
Two masses $ m_1 $ and $ m_2 $ are connected by a massless string over a fixed pulley. If $ m_1 > m_2 $ , $ m_1 $ will move downward and $ m_2 $ will move upward. What is the acceleration with which the combination o f two masses will move?
( $ g = $ acceleration due to gravity)
Updated On: May 2, 2024
- $ 0 $
- $ g $
- $ [(m_1 - m_2)/(m_1 + m_2)] \times g $
- $ [2m_1m_2 /(m_1 + m_2)] \times g $
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The Correct Option is C
Solution and Explanation
$a=\frac{\left(m_{1}-m_{2}\right)\times g}{\left(m_{1}+m_{2}\right)}$
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