Question:

Two identical straight wires are stretched so as to produce $6$ beats per second when vibrating simultaneously. On changing the tension slightly in one of them, the beat frequency still remains unchanged. Denoting by $T_{1}$ and $T_{2},$ the higher and the lower initial tensions in the strings, it could be said that while making the above changes in tension:

Updated On: Aug 1, 2022
  • $T_{1}$ was decreased
  • $T_{1}$ was increased
  • $T_{2}$ was increased
  • $T_{2}$ was decreased
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The Correct Option is A

Solution and Explanation

The relation for frequency and tension is given by $f \propto \sqrt{T}$ As $T_{1}>T_{2}$ i.e., $f_{1}>f_{2}$ So, $f_{1}-f_{2}=6\, Hz$ when we increase lower tension $T_{2}$, then $f_{2}$ will be increased and $f_{1}$ will decrease Hence, $f_{2}-f_{1}=6\, Hz$
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Concepts Used:

Beats

What is Beat Frequency?

Let’s see from fig.m, the frequency of a pink-colored wave is f1, and that of a green-colored wave is f2. So, the frequency of the beat is the difference between these two, which is:

                               fBEATS  = |f1 - f2|

Interference and Beats

When two or more waves travelling in a medium meet, the resulting phenomenon is called interference and beats are an excellent example of the phenomenon of interference. 

What is Interference?

When two or more waves travelling in a medium meet, the resulting phenomenon is called interference and beats are an excellent example of the phenomenon of interference.

The Application of Beats:

  • Beats are used in determining the unknown frequency
  • Beats are used in determining the existence of poisonous gases in mines.