Question:

Two identical satellites $A$ and $B$ revolve around the earth in circular orbits at distance $R$ and $3R$ from the surface of the earth. The ratio of the linear momenta of $A$ and $B$ is ($R$ = radius of the earth)

Updated On: Aug 15, 2022
  • $1 : 1$
  • $1 : \sqrt{2}$
  • $ \sqrt{2} : 1$
  • $2 : 1 $
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The Correct Option is C

Solution and Explanation

Linear momentum of satellite, $p = m \upsilon_0 = m \sqrt{GM/ r} \:\:\: i.e, \, p \propto 1 /\sqrt{r} ;$ $ \therefore \, \frac{p_A}{p_B} = \sqrt{\frac{r_B}{r_A}} = \sqrt{\frac{ R+3R}{R+R}} = \sqrt{2}$
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Concepts Used:

Gravitation

In mechanics, the universal force of attraction acting between all matter is known as Gravity, also called gravitation, . It is the weakest known force in nature.

Newton’s Law of Gravitation

According to Newton’s law of gravitation, “Every particle in the universe attracts every other particle with a force whose magnitude is,

  • F ∝ (M1M2) . . . . (1)
  • (F ∝ 1/r2) . . . . (2)

On combining equations (1) and (2) we get,

F ∝ M1M2/r2

F = G × [M1M2]/r2 . . . . (7)

Or, f(r) = GM1M2/r2

The dimension formula of G is [M-1L3T-2].