Question

Two different dice are tossed together. Find the probability that the product of the number on the top of the dice is 6.

• A. $\frac{1}{4}$
• B. $\frac{1}{6}$
• C. $\frac{1}{3}$
• D. $\frac{1}{9}$

Hint:

List all pairs whose product is the desired number. Probability = (Number of favorable outcomes) / (Total outcomes).

Answer 1

The Correct Option is D

When two dice are tossed, total possible outcomes = $6 \times 6 = 36$. We look for pairs $(x,y)$ such that $x \times y = 6$. The favorable pairs are: \[ (1,6), (2,3), (3,2), (6,1) \] There are 4 favorable outcomes. Hence, probability = $\frac{4}{36} = \frac{1}{9}$.