Two circles intersect at two points B and C. Through B, two line segments ABD and PBQ are drawn to intersect the circles at A, D and P, Q respectively (see Fig. 9.27). Prove that ∠ACP = ∠ QCD


Join chords∠ AP and ∠DQ.
For chord AP,
∠PBA=∠ACP (Angles in the same segment) .... (1)
For chord DQ,
∠DBQ=∠QCD (Angles in the same segment) …. (2)
ABD and PBQ are line segments intersecting at B.
∠PBA=∠DBQ (Vertically opposite angles) .... (3)
From equations (1), (2), and (3), we obtain
∠ACP=∠QCD

(i) The kind of person the doctor is (money, possessions)
(ii) The kind of person he wants to be (appearance, ambition)
ABCD is a quadrilateral in which AD = BC and ∠ DAB = ∠ CBA (see Fig. 7.17). Prove that
(i) ∆ ABD ≅ ∆ BAC
(ii) BD = AC
(iii) ∠ ABD = ∠ BAC.
