Question:
Two cars started moving with initial velocities $v$ and $2v$. For the same deceleration, their respective stopping distances are in the ratio
Two cars started moving with initial velocities $v$ and $2v$. For the same deceleration, their respective stopping distances are in the ratio
Updated On: Aug 15, 2022
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The Correct Option is C
Solution and Explanation
For first car
$v_{1}^{2} =u^{2}-2 a s $
$0 =v-2 a s_{1} $
$s_{1} =\frac{v}{2 a}$
For second car
$ v_{2}^{2}=u^{2}-2 a s$
$0=(2 v)^{2}-2 a s_{2} $
$ s_{2}=\frac{2 v}{a} $
$\therefore \frac{s_{1}}{s_{2}} =\frac{\frac{v}{2 a}}{\frac{2 v}{a}} $
$\therefore \frac{s_{1}}{s_{2}} =\frac{1}{4}$
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Concepts Used:
Motion in a straight line
The motion in a straight line is an object changes its position with respect to its surroundings with time, then it is called in motion. It is a change in the position of an object over time. It is nothing but linear motion.
Types of Linear Motion:
Linear motion is also known as the Rectilinear Motion which are of two types:
- Uniform linear motion with constant velocity or zero acceleration: If a body travels in a straight line by covering an equal amount of distance in an equal interval of time then it is said to have uniform motion.
- Non-Uniform linear motion with variable velocity or non-zero acceleration: Not like the uniform acceleration, the body is said to have a non-uniform motion when the velocity of a body changes by unequal amounts in equal intervals of time. The rate of change of its velocity changes at different points of time during its movement.