Question:

Two cards are drawn at random and without replacement from a pack of 52 playing cards. Find the probability that both the cards are black.

Updated On: Jan 18, 2024
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Solution and Explanation

S = 52 cards
⇒ 52 Two cards are drawn without replacement.

A = {26 black cards}
⇒ n(A) = 26

P(A) = \(\frac {26}{52}\)

And P(B) i.e., the probability that the second card is black known that the first card is black = \(\frac {25}{51}\)

P(A and B) = P(A).P(B)

\(\frac {26}{52} ×\frac {25}{51}\)

\(\frac {1}{2} ×\frac {25}{51}\)

\(\frac {25}{102}\)

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Concepts Used:

Multiplication Theorem on Probability

In accordance with the multiplication rule of probability, the probability of happening of both the events A and B is equal to the product of the probability of B occurring and the conditional probability that event A happens given that event B occurs.

Let's assume, If A and B are dependent events, then the probability of both events occurring at the same time is given by:

\(P(A\cap B) = P(B).P(A|B)\)

Let's assume, If A and B are two independent events in an experiment, then the probability of both events occurring at the same time is given by:

\(P(A \cap B) = P(A).P(B)\)

Read More: Multiplication Theorem on Probability