Question

Two bodies are thrown up at angles of $40^{\circ}$ and $60^{\circ}$ respectively, with the horizontal. If both bodies attain same vertical height, then ratio of velocities with which these are thrown is

• A. $ \sqrt { 2 / 3} $
• B. $ 2 / \sqrt 3 $
• C. $ \sqrt { 3 / 2} $
• D. $ 3 / \sqrt 2 $

Answer 1

The Correct Option is C

$\frac{u_{1}^{2} \sin ^{2} \theta_{1}}{2 g}=\frac{u_{2}^{2} \sin ^{2} \theta_{2}}{2 g}$
or $\frac{u_{1}}{u_{2}}=\frac{\sin \theta_{2}}{\sin \theta_{1}}$
or $\frac{u_{1}}{u_{2}}=\frac{\sin 60^{\circ}}{\sin 45^{\circ}}$
or $\frac{u_{1}}{u_{2}}=\frac{\sqrt{3} / 2}{1 / \sqrt{2}}$
or $\frac{u_{1}}{u_{2}}=\sqrt{\frac{3}{2}}$