Between Any two Red beads there must be at least two Beads. So any Row or column there can be maximum two red beads. If we place two red beads in each row then two columns will have three red bead which cannot be accepted.
The above configuration is not correct.
So in the third row we will place only one Red bead at the middle of the third row. Also we will adjust other rows so that between any two Red beads there are at least two beads in any column.
So maximum 9 Red beads are possible in any configuration. At remaining places Green and Blue coloured beads can be placed in such way that all the conditions given are satisfied. There are multiple configurations are possible. One of the configurations is given as below.
So, the correct option is (C): 9.
To maximize the number of red beads, we need to minimize the number of blue and green beads while still satisfying the given conditions.
One optimal configuration is as follows:
R G R G R
G R G R G
R G R G R
G R G R G
R G R G R
In this configuration, there are:
Therefore, the maximum possible number of red beads in any configuration is 9
Firm | First year of existence | Last year of existence | Total amount raised (Rs. crores) |
---|---|---|---|
Alfloo | 2009 | 2016 | 21 |
Bzygoo | 2012 | 2015 | |
Czechy | 2013 | 9 | |
Drjbna | 2011 | 2015 | 10 |
Elavalaki | 2010 | 13 |
Table 1: 2-day averages for Days through 5 | |||
---|---|---|---|
Day 2 | Day 3 | Day 4 | Day 5 |
15 | 15.5 | 16 | 17 |
Table 2 : Ranks of participants on each day | |||||
---|---|---|---|---|---|
Day 1 | Day 2 | Day 3 | Day 4 | Day 5 | |
Akhil | 1 | 2 | 2 | 3 | 3 |
Bimal | 2 | 3 | 2 | 1 | 1 |
Chatur | 3 | 1 | 1 | 2 | 2 |