Question:

Transmissibility of a confined aquifer having its thickness 15 m and permeability \( 8 \times 10^{-4} \) m/s is given by:

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Transmissibility is calculated as the product of permeability and aquifer thickness. The unit is m²/s.
Updated On: Feb 4, 2025
  • \(1.2 \times 10^{-2} { m}^2/{s}\)
  • \(12 \times 10^{-2} { m}^2/{s}\)
  • \(0.12 \times 10^{-2} { m}^2/{s}\)
  • \(120 \times 10^{-2} { m}^2/{s}\)
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The Correct Option is A

Solution and Explanation

Step 1: Use the formula for transmissibility: \[ T = k \times b \] where: - \( k = 8 \times 10^{-4} \) m/s (permeability), - \( b = 15 \) m (thickness). Step 2: Compute \( T \): \[ T = (8 \times 10^{-4}) \times 15 \] \[ T = 1.2 \times 10^{-2} \, {m}^2/{s} \] Thus, the correct answer is (A) \( 1.2 \times 10^{-2} \) m²/s.
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