Question:

Total number or voids in $0.5$ mole or compound forming hexagonal closed packed structure are

Updated On: Feb 2, 2023
  • $6.022 \times 10^{23}$
  • $ 3.011\times 10^{23}$
  • $ 9.033\times 10^{23}$
  • $ 4.516\times 10^{23}$
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The Correct Option is C

Solution and Explanation

In hexagonal close packed structure, there is 6 atoms per unit cell. $\therefore$ Number of octahedral voids $=6$ $\therefore$ Number of tetrahedral voids $=2 \times 6=12$ Total number of voids $=6+12=18$ $\therefore$ Total number of voids per atom $=\frac{18}{6}$ $= 3$ $\because$ In $1$ mole compound the total number of voids $=3 \times 6.023 \times 10^{23}$ $\therefore$ In $0.5$ mole compound, the total number of voids $=3 \times 0.5 \times 6.023 \times 10^{23}$ $=9.034 \times 10^{23}$
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Concepts Used:

Solid State

Solids are substances that are featured by a definite shape, volume, and high density. In the solid-state, the composed particles are arranged in several manners. Solid-state, in simple terms, means "no moving parts." Thus solid-state electronic devices are the ones inclusive of solid components that don’t change their position. Solid is a state of matter where the composed particles are arranged close to each other. The composed particles can be either atoms, molecules, or ions. 

Solid State

Types of Solids:

Based on the nature of the order that is present in the arrangement of their constituent particles solids can be divided into two types;

  • Amorphous solids behave the same as super cool liquids due to the arrangement of constituent particles in short-range order. They are isotropic and have a broad melting point (range is about greater than 5°C).
  • Crystalline solids have a fixed shape and the constituent particles are arranged in a long-range order.