Toluene on reaction with the reagent X gave Y, which dissolves in NaHCO\( _3 \) and when reacted with Br\( _2 \)/Fe gave Z. What are X and Z?
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The Correct Option is D
Solution and Explanation
Toluene reacts with KMnO\( _4 \)/OH\( ^- \), \(\Delta\) followed by H\( _3 \)O\( ^+ \) to give benzoic acid (Y). Benzoic acid dissolves in NaHCO\( _3 \) due to the formation of sodium benzoate. When benzoic acid reacts with Br\( _2 \)/Fe, it undergoes electrophilic substitution. The -COOH group is a deactivating and meta-directing group. So, the bromine atom will be substituted at the meta position. Thus, X is KMnO\( _4 \)/OH\( ^- \), \(\Delta\) followed by H\( _3 \)O\( ^+ \) and Z is m-bromobenzoic acid.
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